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2
                                                   P x    N   S  m x
                                                                                                          (1.5.4)
                                                     t        V
            According to Newton's second law, this equals the average force exerted
            by the wall area S on the molecules; from the third law, this is the negative

            of the force exerted on the wall by the molecules. Finally, pressure   p is
            force per unit area, and we obtain
                                                                  2
                                                      F     N  m x
                                                         p                                               (1.5.5)
                                                      S       V
                In fact,   v  is not now the same for all molecules. But we could have

                             x
            sorted them into groups having the same v  within each group, and added
                                                                    x
            up the resulting contributions to the pressure. The net    effect of this is
                                      2
                                                                                             2
            simply to replace  v  in Eq. (20-5) by the average value of   v   which we
                                                                                             x
                                      x
                                                     2
                            2
            denote by  v  . Furthermore   v   ,  is related simply to the speeds of the
                            x
                                                     x
            molecules. The speed  v (magnitude of velocity) of any molecule is related
            to the velocity components  v ,   v   and    v        by
                                                         y
                                                  x
                                                                      z
                                                                    2
                                                              2
                                                        2
                                                  2
                                                        v   v  v   v                                       (1.5.6)
                                                        x     y     z
             This may be averaged over all molecules   which move with different
             speeds    v ,  v ... v :
                                   N
                          1
                              2
                                                     2
                                                                       2
                                                           2
                                                                 2
                                                             v   v   v   v rms                                 (1.5.7)
                                                           y
                                                     x
                                                                 z
             Where v    rms  is root-mean-square speed  and it is equal to

                                                  2
                                                        2
                                                 v    v    ...  v 2
                                            v    1     2          N                                       (1.5.8)
                                       rms
                                                          N
                                                                             v   v ...  v
              (N.B. the average or mean speed is equal to  v               1    2         N  )
                                                                                     N
             since the x-, y-, and z-directions are all  equivalent,

                                                      2     2     2
                                                              v   v   v                                        (1.5.9)
                                                                  z
                                                      x
                                                            y
             Hence
                                                    2    1   2
                                                            v   v rms                                           (1.5.10)
                                                    x
                                                         3
            and eq. (20-5) becomes





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