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Distance from the point to the line


                                                            {       2        2
                                                               (µA) + (µB) = 1,
                 two properties of a normal equation are true:                       From the first condition:
                                                               µC < 0.
                                                                1
                                                      µ =    √                                        (6.15)
                                                                2
                                                           ± A + B    2
                     The sign can be chosen from the second condition: it must be opposite to the sign of a free
                 term in a general equation when C ̸= 0. The sign of µ is arbitrary in case C = 0. Digit µ is
                 called as a normal multiplier.



                       6.6. Distance from the point to the line

                                                           −→
                 Let’s assume, there is line l, normal-vector n and point M 0 (x 0 ; y 0 ), that doesn’t belong to the
                 line (fig. 6.15). Let’s solve the task about finding the distance from the point to the line. Let’s
                                                                              −−→
                 mark the distance as d (fig. 6.15). Radius-vector of point M 0 : OM 0 = (x 0 ; y 0 ). Let’s find the
                 projection of this radius-vector on a normal to the line. Depending on the location of point M 0 ,
                                                                      −−→
                 this projection can be calculated by the formula: pr−→ 0OM 0 = p ± d. In case the beginning of
                                                                   n
                 coordinates and the point are located on the same side, it equals to p+d. In case they are located
                 on different sides, it equals to p − d.

                                                      y


                                                            d    M 0
                                                                    Q
                                                              d
                                                        − 0 n  N
                                                        →
                                                        . . . . . . . . . . . .  α
                                                      O                  x

                                                                     l
                                        Figure 6.15 – Distance from the point to the line


                     Let’s write a scalar product: x 0 cos α + y 0 sin α − p = ±d. In this equality digit d is always
                 positive. A substitution of coordinates of point M 0 in the left part of the last equation, that is
                 called as a rejection of point M 0 from the line, is either positive or negative. So, the difference
                 equals to:
                                                 δ = x 0 cos α + y 0 sin α − p.                       (6.16)
                     Distance d = |δ| , meaning


                                                d = |x 0 cos α + y 0 sin α − p| .                     (6.17)

                                    A                B              C
                     But cos α = √       , cos β = √      , p = − √      . So
                                                     2
                                    2
                                                                    2
                                   A +B 2           A +B  2        A +B 2
                                                        |Ax 0 + By 0 + C|
                                                    d =    √             .                            (6.18)
                                                               2
                                                             A + B   2
                     The distance from the point to the line can be calculated by the means of formula (6.18).
                 Note, when calculating the distance from the point to the line, it is useful to have a normal
                 equation of line (6.14). Then, having substituted coordinates of point M 0 (x 0 ; y 0 ) in this equation,
                 and having taken it’s left part by module, we will obtain the distance.




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