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Partial Fractions


                   Theorem 2.14È


                   (Heaviside Expansion Theorem) If F(s) is the quotient P(s)/Q(s) of two
                   polynomials in s such that Q(s) has the higher degree and contains simple

                   poles the factor s − s , which are not repeated, then the term in f(t)
                                               k
                                                                            P(s k )  s k t
                   corresponding to this factor can be written                    e
                                                                           Q (1) (s k )
               . . . . . . .
                .

                   Example 2.35, Find the inverse Laplace transform of the
                   following function using the Heaviside expansion theorem:


                                                        (               )
                                                              s − 3
                                                     −1
                                                   L                       .
                                                            2
                                                           s + 5s + 6
               . . . . .
                .
                   Solution. We write in form

                                              P(s)         s − 3               s − 3
                                    F(s) =          =                 =                   .
                                                         2
                                              Q(s)      s + 5s + 6       (s + 2)(s + 3)
                   The derivative of the denominator is


                                                        (1)
                                                      Q (s) = 2s + 5

                   from which, for the roots of this equation,

                                               (1)
                                                                 (1)
                                             Q (−2) = 1, Q (−3) = −1.
                   Hence, P(−2) = −5, P(−3) = −6. The final value for f(t) is f(t) =

               . . . .  −5e −2t  + 6e −3t .
                .


                   Example 2.36, Find the inverse Laplace transform of the
                   following function using the Heaviside expansion theorem:

                                                        (               )
                                                              2s + 3
                                                     −1
                                                   L                       .
                                                            2
                                                           s + 4s + 7
               . . . . .
                .
                   Solution. The roots of the denominator are

                                                                   √                √
                                       2
                                      s + 4s + 7 = (s + 2 + i 3)(s + 2 − i s).

                   That is, the roots of the denominator are complex. The derivative of the
                   denominator is
                                                        (1)
               . . . .                               Q (s) = 2s + 4.


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