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P. 56

As  z   , y  the last equation is Equation of the first order of
                                 relatively  unknown  function  у(х)  which  gets  untied  by
                                 integration:
                                                            1      c  1  1   c  1   c  1
                                                      1
                                                    c
                                        c
                                         1
                                                                                    
                                                 
                                    y   xe  1 x  ,  y   xe  1 x  dx      xd (e  1 x  )    (xe  1 x   e  1 x  dx )  
                                                            c 1          c 1
                                    1    c  1  1  c  1       c  x  1  c  1
                                     (xe  1 x    e  1 x  ) c   2  1  e  1 x    c 2  .
                                   c           c               c  2
                                    1           1               1

                                     Consequently,    the    common     decision    was    got
                                     c  x  1
                                  y   1    e c 1 x 1    c 2  .
                                       c 2
                                        1

                                     We  find  the  value  of  constant  с 1  and  с 2  from  initial
                                 conditions  1(y  )   e , y  ) 1 (   e 2 . Obsessed system of equations:
                                         c   1   1       2     1 
                                      e    1  e  1 c   c  2  , e   e  1 c  ,
                                          c 1 2

                                 from which we find easily, that с 1=1, с 2=е.
                                     Therefore  the  sought  decision  after  part  of  the  given
                                 equation is determined by a formula
                                      y   (x   ) 1 e x 1    . e 

                                     Example  3.5      A  body  by  mass  m   falls  free  from  some
                                 height  without  initial  velocity.  At  falling  a  body  tests
                                 proportional to the square of speed of body. To find the law of
                                 motion of body.

                                        Lets  s   s  ) (t  - the way passed by a body in times of  t
                                                                   ds     d  2 s
                                 from the beginning of motion, then     v,     w  – speed and
                                                                   dt     dt 2
                                 acceleration of motion accordingly.



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