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1

 Here is n . After replacement y  uv , y  u v  v u 
2
we will get
 vu 
x  v u   4uv  x 2 uv ,
4uv
u v  v u    x uv ,
x

 4v 
u v  u v      x uv .
 x 

After the known algorithm we come to the system

 4v
   v  ,0
 x
 u v  x uv .


4
The first equation has the decision v  x , and the second
acquires a kind xu 4  x 3 u or at x 0
du dx
 ,
u x
du dx
   ,
u x
1
2
2 u  ln x  ln C , u  ln Cx .
4
Then common decision of the given equation:
x 4 2
y  ln Cx . 
4

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