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 We will write down equation in a kind:
1

y  .
2xy  y 3

This equation is not linear, but, if to change the roles of the
sought function after and argument, we will get equation linear
relatively unknown function   yx and its derivative:
3
x   2yx  y .
We will untie him by a method Bernoulli:

x  uv, x  u v  v u  . We consider here, that
u  u   y , v  v   y .
Then
u v  v u   2uvy  y 3 ,

u v  u v   2vy  y 3 .

   2vyv  ,0
We have 
 u v  y 3 .

We decide the first equation of the system:
dv
 2ydy ,
v
2
lnv  y  lnC ,
2
y
v  Ce .
We will put the got function v  v  y in the second equation
of the system:

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