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x
                                     .             u     P  yx,  dx     y                                        (2.5)

                                                 x 0

                                     In  this case  a  variable    is  fixed  and  the  arbitrary  became
                                 integration  has  the  appearance  of  arbitrary  function  from  y .
                                 We will choose    y   thus, that the second was executed with
                                 (2.4).  For  this  purpose  we  integrate  (2.5)  on  and  will  equate
                                 to  yxQ ,  :
                                           x
                                       u    P
                                             dx     Qy    , yx  .
                                       y     y 
                                           0 x

                                                                P    Q
                                     As from a condition (2.3)         , it is possible to write
                                                                 y   x 
                                        x   Q
                                 down      dx     Qy    yx,  , from where, taking into account
                                          x 
                                       x 0
                                 scopes   of   integration   Q  yx,   Q  x ,   y     Qy    yx,  ,
                                                                         0
                                 obsessed, consequently

                                            Qy   x ,   y                                                               (2.6)
                                                0

                                             y
                                         Qy    x ,  y dy                                                         (2.7)
                                                 0
                                            y 0

                                     Such integration is possible only on condition that equality
                                 (2.6) does not contain a variable  x  obviously, in opposite case it
                                 is needed to search an error: either equation was not in complete
                                 differentials or calculation were viciously.
                                     We will put a result (2.7) in (2.5):
                                                  x            y
                                     .              u     P  yx,  dx    Q x ,  y dy                          (2.8)
                                                                    0
                                                  x 0          y 0
                                                               18
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