Page 16 - 4549
P. 16

We will notice that the arbitrary became was written down
                                 in a logarithmic kind as  ln  C , to it will be succeeded and farther
                                 with  the  purpose  of  simplification of  eventual  result.  We  will
                                 mark  in  addition,  whatever  no  upshots  were  lost,  as
                                 1 x 2  1 e  y   0   at  x   R,  y   R  .  Thus,  sought  common
                                 decision after  

                                     Example 1.3 To find the decision of Cauchy task
                                                       x 3    y  y    , 7  y   51   .
                                        We  will  rewrite  equation  x 3  y   7   , y    in  a  kind
                                                                        
                                      7   y
                                   
                                  y       ,  and then answers as (1.15). To separate variables in
                                       x 3
                                 this  case  it  is  needed  to  write  down  derivative  in
                                                 dy
                                              
                                 differentials y   :
                                                 dx
                                      dy   7   y             dy      dx
                                                 and farther           .
                                      dx    x 3              y   7   x 3

                                     Equation   with the separated variables, which we integrate
                                    dy       dx
                                            3    and  will  as  a  result  get  a  general  integral
                                   y   7    x
                                            1
                                 ln  y  7       C , was got . We will find an integral part now
                                             x 2  2
                                 that      satisfies    an       initial    condition   51 y  :
                                             1                  1
                                 ln  5   7     C , C    ln  2   .  Consequently, the decision
                                           2  1   2            2
                                                                   1         1
                                 of Cauchy task will be   ln y  7     ln  2   .
                                                                  2x  2      2

                                     Before equation with the separated variables the equations
                                 of kind are erected

                                           
                                             y   f  ax   by   , c                                                 (1.20)
                                                               14
   11   12   13   14   15   16   17   18   19   20   21