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X
where max — anomalous value among all factors;
X — average value of factor.

2. Evaluate:

  c S (4.25)
max x ,
where C — constant, which is calculated by Student’s
criteria t by equation:
5 , 0

N c  2  f  f   1
0  t 0 f  f ,
2
 N  c  q . 0 05 (4.26)
f f   f  
 0 
 f 

where N — number of values, remaining after the
discarding of abnormal one;
f = N -l — number of degrees of freedom;
f o — number of additional degrees of freedom (can
choose f o = 0);
q — level of significance of freedom, that characterizes
degree of probability (in technical calculations q = 0.05).
Square root mean deviation for the sample of factors,
remained after discarding of abnormal factor, is determined by
formula:

1 N 2
S    (X  X ) , (4.27)
x N  1 u
u  1
X
Abnormal value max is rejected if inequality (4.27) is
satisfied.

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