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P. 64

Solved Problems


               that satisfies the inhomogeneous boundary conditions.

                                                    q(x)
                                             00
                                           µ = −          ,   µ (0) = µ (h) = 0
                                                                p
                                                                          p
                                             p
                                                      κ
                                             00
                                            µ = 0,      µ (0) = a,      µ (h) = b
                                                          h
                                                                         h
                                             h
                   We find the particular solution µ with the method of Green functions.
                                                         p
                                          00
                                        G = δ(x − ξ),        G(0|ξ) = G(h|ξ) = 0.
               We find homogeneous solutions which respectively satisfy the left and right homo-
               geneous boundary conditions.

                                                   y = x,      y = h − x
                                                                2
                                                     1
               Then we compute the Wronskian of these solutions and write down the Green
               function.


                                                          x h − x

                                                  W =                = −h
                                                          1    −1

                                                               1
                                                G(x|ξ) = − x (h − x )
                                                                  <
                                                                            >
                                                               h
                   The homogeneous solution that satisfies the inhomogeneous boundary conditions
               is
                                                                  b − a
                                                      µ = a +           x
                                                       h
                                                                    h
                   Now we have the equilibrium temperature.

                                           b − a       Z  h   1                   q(ξ)
                                 µ = a +          x +       − x (h − x ) −                 dξ
                                                                           >
                                                                 <
                                              h          0    h                      κ
                                      b − a       h − x  Z  x               x  Z  h
                           µ = a +          x +               ξq(ξ) dξ +           (h − ξ)q(ξ) dξ
                                        h          hκ      0               hκ   x

                   Let v denote the deviation from the equilibrium temperature.

                                                          u = µ + v


               v satisfies a heat equation with homogeneous boundary conditions and no source
               term.
                             v = κv ,       v(0, t) = v(h, t) = 0,      v(x, 0) = f(x) − µ(x)
                                      xx
                              t
               We solve the problem for v with separation of variables.


                                                       v = X(x)T(t)
                                                            0
                                                                     00
                                                       XT = κX T
                                                      T  0    X 00
                                                           =       = −λ
                                                      κT      X


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