Page 25 - 6637
P. 25

Supplementary Problems


                                                         φ = −φ − iφ       β
                                                          ψ
                                                                   α
                                                       φ ξψ  = −φ  αα  − φ ββ

                     We transform the equation to canonical form.

                                                                   φ + φ   ψ
                                                                     ξ
                                                       φ ξψ  = −
                                                                  12(ξ + ψ)
                                                                         −2iφ  β
                                                    −φ  αα  − φ ββ  = −
                                                                          12iβ

                                                                          φ β
                                                        φ αα  + φ ββ  = −
                                                                          6β







               3.2      Supplementary Problems

               Exercise 68. Determine the type of the PDEs. By means of a method of char-

               acteristics bring PDEs to its canonical view:
                                                   2
                    2
                                                                               2
                              2
               a) x u  xx  − y u yy  = 0;   b) sin xu   xx  − 2y sin xu xy  + y u yy  = 0;
               c) u xx  − 2u xy  + 2u yy  = 0.
                                                                                                       2
                                                                                                3
               Exercise 69. What is the order of the following equations (a)                  ∂ u  +  ∂ u  = 0,
                                                                                              ∂x 3    ∂y 2
                               4
                                       2
                     2
               (b)  ∂ u  − 2  ∂ u  +  ∂ u  = 0?
                               2
                    ∂x 2     ∂x ∂y    ∂y 2
                                                                                                              2
               Exercise 70. Classify the following differential equations (as elliptic, etc.) (a)            ∂ u −
                                                                                                            ∂x 2
                                                                         2
                                                                                                        2
                                                                   2
                                                                                                2
                                               2
                                        2
                          2
                   2
               2  ∂ u  +  ∂ u  = 0, (b)  ∂ u  +  ∂ u +  ∂u  = 0, (c)  ∂ u −  ∂ u +2 ∂u  = 0, (d) y  ∂ u +x ∂ u  = 0.
                 ∂x∂y    ∂y 2          ∂x 2   ∂y 2  ∂x           ∂x 2   ∂y 2   ∂y              ∂x 2   ∂y 2
               Exercise 71. What are the types of the following equations?                   (a) u xx  − u xy  +
               2u + u − 3u       yx  + 4u = 0. (b) 9u    xx  + 6u xy  + u + u = 0.
                                                                         yy
                         yy
                                                                                x
                  y
               Exercise 72. Find the regions in the xy-plane where the equation (1 + x)u                   xx  +
                             2
               2xyu  xy  − y u yy  = 0 is elliptic, hyperbolic, or parabolic. Sketch them.
               Exercise 73. What is the type of the equation u             xx  − 4u + 4u    yy  = 0? Show by
                                                                                   xy
               direct substitution that u(x, y) = f(y + 2x) + xg(y + 2x) is a solution for arbitrary
               functions f and g.
               Exercise 74. Reduce the elliptic equation u           xx  + 3u − 2u + 24u + 5u = 0 to
                                                                                       x
                                                                              yy
                                                                                                y
               the form v   xx  + v yy  + cv = 0 by a change of dependent variable u = ve           αx+βy   and
                                            0
               then a change of scale y = γy.
               Exercise 75. Consider the equation 3u +u             xy  = 0. (a) What is its type? (b) Find
                                                               y
               the general solution (Hint: Substitute v = u ) (c) With the auxiliary conditions
                                                                     y
               u(x, 0) = e   −3x  and u (x, 0) = 0, does a solution exist? Is it unique?
                                        y
                                                              21
   20   21   22   23   24   25   26   27   28   29   30