Page 16 - 4911
P. 16
7.3 The stoichiometric flow rate of dry air for combustion of 1 kg of solid or liquid fuels
3
[6], m /kg
P
P
P
P
O
V = 0,0889·(C + 0,375·S ) + 0,265·H – 0,0333·O . (7.3)
3
7.4 The stoichiometric flow rate of а dry air for the combustion of 1 m of а gaseous
fuel.
O
V = (0,5·CO + 0,5·H 2 + 1,5·H 2S + Σ(n + m/4)·C nH m – O 2)/21 , (7.4)
where
O
3
3
V - stoichiometric air consumption , m /m ;
CO, H 2, H 2S, O 2 - volume concentration in the fuel oxide carbon hydrogen,
hydrogen sulfide, oxygen, %;
n,m - is the number of atoms, respectively, of carbon and hydrogen in chemical
connected CnHm;
CnHm - volume concentration in the hydrocarbon fuel, consists of n atoms C ,
and m atoms H, %.
7.5 The volume of the components of the combustion products of 1 kg of liquid (solid)
the fuel at excess air coefficient.
P
v 18 ,67 10 3 C ; (7.5)
carbon dioxide co
2
o
P
v 0 ,79 V 8 10 3 N ; (7.6)
nitrogen N
2
V 0 ,21 ( 1 ) V o ; (7.7)
oxygen O 2
sulfur dioxide V so 2 7 10 3 S P
A ; (7.8)
P
P
water vapor V 0 ,111 H 0 ,0124 W 1 ,24 W 0 ,0161 V o (7.9)
H 2 O ф
In the formula (4.9) is denoted by:
W F - moisture injection or steam atomization of fuel, kg/kg
Mostly steam nozzle use 0,3 ÷ 0,5 kg of steam per 1 kg of fuel oil [7.p 277]. For the
oil-gas burners with steam atomization of fuel can be taken W F = 0.05 kg/kg [6, p. 355].
3
7.6 The amount of combustion products which are produced from 1 m of the fuel gas:
n
v
carbon dioxide co = 0,01·(CO 2 + CO + n C nH m); (7.10)
2
i 1
v
oxygen o = 0,21·(α – 1)·V˚ (7.11)
2
v
nitrogen N = 0,79·α·V° + 0,01·N 2 (7.12)
2
v
sulfur dioxide so = 0,01·H 2S; (7.13)
2
16