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7.3 The stoichiometric flow rate of dry air for combustion of 1 kg of solid or liquid fuels
                   3
            [6], m /kg

                                     P
                                                  P
                                                                               P
                                                                 P
                     O
                   V  = 0,0889·(C  + 0,375·S ) + 0,265·H  – 0,0333·O .                                (7.3)

                                                                                           3
            7.4 The stoichiometric flow rate of а dry air for the combustion of 1 m  of а gaseous
            fuel.

                     O
                   V  = (0,5·CO + 0,5·H 2  + 1,5·H 2S + Σ(n + m/4)·C nH m – O 2)/21 ,              (7.4)
            where
                      O
                                                                3
                                                                    3
                       V  - stoichiometric air consumption , m /m ;
                       CO, H 2, H 2S, O 2  - volume concentration in the fuel oxide carbon hydrogen,
            hydrogen sulfide, oxygen, %;
                       n,m  - is the number of atoms, respectively, of carbon and hydrogen in chemical
            connected CnHm;
                      CnHm - volume concentration in the hydrocarbon fuel,  consists of n atoms C ,
            and m atoms H, %.

            7.5 The volume of the components of the combustion products of 1 kg of liquid (solid)
            the fuel at excess air coefficient.

                                                               P
                                          v    18 ,67 10 3    C  ;                                                    (7.5)
            carbon dioxide                   co
                                             2
                                                   o
                                                               P
                                   v     0 ,79  V   8 10  3  N ;                                                     (7.6)
            nitrogen                    N
                                      2
                                       V    0 ,21  (    1 )  V   o   ;                                                          (7.7)
            oxygen                           O 2
            sulfur dioxide                  V so 2   7  10 3  S   P
                                                         A  ;                                                             (7.8)
                                                P
                                                              P
            water vapor        V      0 ,111   H  0 ,0124   W 1 ,24   W  0 ,0161     V   o                      (7.9)
                                 H 2 O                                  ф
            In the formula (4.9) is denoted by:
                 W F - moisture injection or steam atomization of fuel, kg/kg

                Mostly steam nozzle use 0,3 ÷ 0,5 kg of steam per 1 kg of fuel oil [7.p 277]. For the
            oil-gas burners with steam atomization of fuel can be taken W F = 0.05 kg/kg [6, p. 355].


                                                                                           3
            7.6 The amount of combustion products which are produced from 1 m  of the fuel gas:

                                                                             n
                                              v
                   carbon dioxide                  co  = 0,01·(CO 2 + CO +    n C nH m);                 (7.10)
                                                  2
                                                                             i 1
                                                v
                   oxygen                                o  = 0,21·(α – 1)·V˚                                           (7.11)
                                                  2
                                                      v
                   nitrogen                                       N  = 0,79·α·V° + 0,01·N 2                   (7.12)
                                                         2
                                                           v
                   sulfur dioxide                                      so  = 0,01·H 2S;                                  (7.13)
                                                              2

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