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For uniformly accelerated motion modulus of acceleration can
                  be calculated
                                                     v   v 0
                                                        a 
                                                        t       .                                                 (1.18)

                                                                      where    v  is initial speed  and
                                                                                   0
                                                                   v - final speed (not velocity)
                                                                      From 1.18 follows

                                                                           v   v    t a   .                   (1.19)
                                                                                0
                                                                      Speed-time  graph  of  such

                                                                   uniformly accelerated    motion is
                                                                   shown in fig.1.7
                                                                      For  infinitely  small  time  dt  we
                                                                   can  consider  uneven  motion  as

                                                                   uniform  one  so  that  infinitely
                                                                   small  distance  dS  passed  by  this
                            Figure 1.7
                                                                   time is equal to


                                                      dS   v   dt        .                                            (1.19)


                     The total distance we calculate as a definite  integral


                                    t            t                                2
                                                                             a  t
                              S   v    dt    (   v 0   dt) dt   tv 0  
                                    
                                                 
                                    0            0                              2       .                   (1.20)

                     I.e. in this case distance is numerically equal to the area of trapezium
                  – sum of area of rectangle and triangle


                                     1.5. Acceleration  of Curvilinear Motion



                     If  material  point  moves  by  arbitrary  curve,  the  vector  of  velocity.
                  changes  direction. Simultaneously, modulus of velocity  can change as
                  well. Therefore  there are two accelerations of material point .

                     . Consider  in detail these accelerations as shown in  fig.1.9.







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