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          
  1 2 3 4 5 6 
a
6
, 0 01167  , 0 02167  , 0 01833  , 0 03833  , 0 03167  , 0 00833
 
6

2
 , 0 02167 mkm .

Root mean square deviation is determined by the formula:
2 2 2 2 2 2
          
S  1 2 3 4 5 6 
n
2 2 2 2 2 2
, 0 01167  , 0 02167  , 0 01833  , 0 03833  , 0 03167  , 0 00833
  , 0 024mkm 2
6

Relative error of measurements is determined by the formula:
 , 0 02167
  a  100 %   100 %  13 4 , %
k , 0 16167
a

2
Answer: the root mean square deviation is S=0,024 mkm ;
2
Absolute error  a  , 0 02167 mkm . and relative error of
measurement  13 4 , % .
Task 1.2
Determine the root mean square deviation, absolute and
relative measurement error for the filtration rate of the fluid by the
law of Darcy for such values of pressure p = 1,2; 1,5; 1,1; 1,7;
1,4 MPa; if the length of the sample of rock  l  2 (  ) n cm
(where n - number of student’s variant); liquid density - 870
-7
3
kg/m ; filtration coefficient - 3,810 m/s; acceleration of gravity -
2
9.81 m/s .

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