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distribution of a random variable.

                Task 1.1
                During the study, the gas permeability of rock sample at a
                                                        0
           pressure of 40 MPa and a temperature of 80  С got six values of
                                            2
           coefficient  of  permeability,  mkm :  0.15;  0.14;  0.18;  0.2;  0.13;
           0.17.  Determine  the  root  mean  square deviation,  absolute  and
           relative measurement error.
                Solving:
                Arithmetic  mean  value  of  the  measurement  results  is
           determined by the formula:
                      k   k   k   k   k   k
                 k    1   2    3   4    5   6
                  a               6

                       , 0 15  , 0 14   , 0  18  2 , 0   , 0  13  , 0  17
                                                                       2
                 k                                       , 0  16167  mkm .
                  a                   6
                Absolute  errors  of  measurement  are  determined  by  the
           formulas:

                                                              2
                    k   k    , 0  15  , 0 16167   , 0  01167  mkm ;
                  1    1   a
                                                              2
                    k   k     , 0 14   , 0 16167   , 0  02167  mkm ;
                  2    2    a
                                                              2
                    k   k    , 0  18  , 0  16167   , 0  01833 mkm ;
                  3    3    a
                                                             2
                    k   k     2 , 0   , 0  16167   , 0  03833  mkm ;
                  4    4    a
                                                               2
                    k   k     , 0  13   , 0 16167   , 0  03167  mkm ;
                  5    5    a
                                                              2
                    k  k      , 0  17   , 0 16167   , 0  00833 mkm .
                  6    6    a
           Determining  arithmetic  mean  value  of  absolute  error  by  the
           formula:
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