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displacement  of  oil  by  water,  which  states  that  the  residual  oil
          saturation behind the front displacement remains constant. This is
          the perfect case oil displacement when the layer between oil and
          water creates a clear border section, which moves ahead of oil and
          behind  only  water.  And  as  shown  by  laboratory  and  industrial
          researches  front  displacement  is  a  compatible  flow  of  water  and
          oil. Filtration resistances in the zone of oil replacement water will
          differ  from  the  filtration  resistances  calculated  at  scheme
          homogeneous  liquid  piston  displacement.  Therefore,  it  can
          consider this fact can lead to errors in determining the flow rates
          and validities.
                  It is established that the ratio of the viscosity of oil to the
          viscosity  of  water   0= oil/ w,  which  ranges  from  1  to  10  in  the
          displacement of oil by water can be taken
                         m  V
                   z       0   ,                                                           (3.19)
                        150Q (t )

          where z= o- ro ; m – coefficient of porosity; V – the volume of the
          layer; Q(t) - the total amount of water that entered in the reservoir.
          Equation (19) defines oil saturation at any point depending on its
          position.  Oil  saturation  at  the  front  oil  water  displacement  is
          determined by the formula
                                     
                   z  1,0            0          ,   f. u.                      (3.20)
                    f
                             5 , 1    1  r  o    bw  z  ф
          where  0= oil/ w;  r o - residual oil saturation, f.u.;  b w - saturation
          of bound water, f.u.
                  Equation (3.20) is  solved the graphic-analytical  method.
          For  this  first  from  the  equation  (3.20)  is  determined  the  value
          1- r o -  b w.
                  To do this, the left and right sides of the equation (3.20)
          to lift the square. We obtain









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