Page 87 - 4549
P. 87

 C  )(x  y   C  ( yx )   ,0
                                                      1  1  2   2                                  (6.8)
                                               C 1  )(x  1  y   C  2  (x )   y  2   (xf  ).

                                      As a determinant of this system     W  ( )x   (Wronskian
                                                                                0
                                 of linearly independent decisions of LHDE) system of equations
                                 (6.6), (6.7) has the upshots.
                                                                                         
                                         Solving  of  the  system  (6.8)  we  will  find  С  (х ),С  (х )
                                                                                   1     2
                                 and than C  ( ),x C  ( )x .
                                           1      2
                                                       ~                       ~
                                     С  (х )   С 1   (х )dx   С  (х ),С  (х )   С 2   (х )dx   С  (х )   (6.9)
                                       1                 1     2                   2

                                     As we search the partial decision of LNDE only during this
                                 integration arbitrary constant it is possible to scorn.
                                     Putting the found values C  ( )x  and C  ( )x  in (6.5) we shall
                                                               1         2
                                 get obsessed partial decision.

                                     Example 6.1   To untie a task Cauchy
                                                  1
                                                                          2
                                           y   y   ,  y (0) 1 , y (0)  .
                                                              
                                                1 e  x

                                   a) At first we will search the common decision of the proper
                                 homogeneous equation   y   y   0.
                                     Characteristic equation:
                                                          2      , 0
                                                          (   ) 1   , 0
                                                          1    , 0  2    1

                                                               x
                                 partial  decision:  y   1, y   e   they  are  linearly  independent.
                                                   1      2
                                 Consequently, the common decision of homogeneous equation
                                 has a kind :
                                                                      x
                                                           
                                                           y   C   C e .
                                                                1   2

                                                               85
   82   83   84   85   86   87   88   89   90   91   92