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Supplementary Problems


                                                         Z    b
                                           (2n − 1)πa      2                   (2n − 1)πy
                            γ = csch                              f (y) cos                     dy
                              n
                                                                   1
                                                2b         b   0                    2b
                                       ∞
                                                    (2n − 1)πy              (2n − 1)πa
                                     X
                          v(a, y) =       δ cos                     sinh                    = f (y)
                                           n
                                                                                                 2
                                                         2b                      2b
                                      n=1
                                                        Z     b
                                           (2n − 1)πa      2                   (2n − 1)πy
                             δ = csch                             f (y) cos                     dy
                              n
                                                                   2
                                                2b         b   0                    2b
               With u and v determined, the solution of the original problem is w = u + v.

               10.2       Supplementary Problems

                                                                                                        n
                                                                            n
               Exercise 206. Prove that the functions u(r, θ) = r cos nθ and u(r, θ) = r sin nθ
               are harmonic for every n = 0, 1, 2, . . . .

               Exercise 207. Find a the steady-state distribution of temperature of a circular
               membrane, if the temperature is kept fixed and equal to 1 in half the boundary, and
               −1 in the other half:

                                                           −1, −π < θ < 0
               ∆u = 0 for r < a,            u(a, θ) =
                                                             1,    0 < θ < π

               Exercise 208. Find the solutions that depend only on r of the equation u                   xx  +
                                2
               u + u    zz  = k u, where k is a positive constant. (Hint: Substitute u = v/r.)
                 yy
               Exercise 209. Solve u         xx  + u yy  + u zz  = 0 in the spherical shell 0 < a < r < b
               with the boundary conditions u = A on r = a and u = B on r = b, where A and

               B are constants. (Hint: Look for a solution depending only on r.)

               Exercise 210. Solve u        xx  + u yy  = 1 in r < a with u(x, y) vanishing on r = a.


               Exercise 211. Solve u         xx  + u yy  = 1 in the annulus a < r < b with u(x, y)
               vanishing on both parts of the boundary r = a and r = b.


               Exercise 212. Solve u         xx  + u yy  + u zz  = 1 in the spherical shell a < r < b with
               u(x, y, z) vanishing on both the inner and outer boundaries.


               Exercise 213. Solve u         xx  + u yy  + u zz  = 1 in the spherical shell a < r < b with
               u = 0 on r = a and ∂u/∂r = 0 on r = b. Then let a → 0 in your answer and
               interpret the result.


               Exercise 214. A spherical shell with inner radius 1 and outer radius 2 has a
                                                                                                        ◦
               steady-state temperature distribution. Its inner boundary is held at 100 C. Its
               outer boundary satisfies ∂u/∂r = −γ < 0, where γ is a constant.
                 (a) Find the temperature.



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