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Step 2

2
2
2
2
D   x   y  778 . 42  3701 . 68  3782 . 64 ft ;
1 2
Step 3
Since line 1-2 lies in the northeast quadrant (I), the reference direction is
North.
Step 4

1 y
1


b  tan    tan  3701 . 68  78  0 7 8 2  ,


1 2
 x   778 . 42 
Step 5
This is the local angle relative to North and situated in I quadrant.
That’s why b 1-2=A 1-2.
A  78  0 7 2 8
1 2

Solution: Line 1-2, azimuth 78˚07’28”, length 3782.64 ft.

INVERSE PRACTICE PROBLEM
Using UTM coordinates of points 1, 2, 3 (Practical work №2) make inverse
computations for directions 1-2; 2-3; 3-1.

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