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2
2
2. Determine length using: D   x   y ;

3. Determine the number of quadrant (I – NE, II – SE, III – SW, IV – NW);

 y 
1
4. Determine the bearing of direction 1-2: b 1 2  tan   ;
 x 
5. Determine the azimuth of direction A 1-2.

INVERSE EXAMPLE PROBLEM
Inverse from Point 1 to Point 2.

Number of UTM coordinates
point X Y
1 3913.66 2207.65
2 4692.08 5909.33

Step 1
Direction 1-2 X Y
Destination Point 2 _ 4692.08 _ 5909.33

Origin Point 1 3913.66 2207.65
Δx=+ 778.42 Δy=+ 3701.68

Note that Δx and Δy are both positive, thus line 1-2 lies in the northeast
quadrant

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