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(Mg)

the oxidizer +5 +4
N + 1ē → N 2 the reduction process
(HNO 3)

+5
+2
0
+4
Mg +4HN O 3 = Mg (NO 3) 2+2N O 2+2H 2O

For example 4:

5  2  o -1 0
K Cl O 3  t K 2 O Cl

-2 0
the reducing agent 2O − 4ē → O 3 the oxidation process
2
the reduction process

+5 -1
the oxidizer Сl + 6ē → Cl 2

5  2  o -1 0
2K Cl O 3  t 2K Cl 3  2 O

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