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back at an angle  – angle at the point K . The arc KK   d
 1
and the triangle CKK – KK   dx . Equating the right of
1 1 
expression, we obtain
d
   . (5.4)

dx

Figure 5.5

We have obtained the linear law of distribution of angular
deformitions along the radius. This is because the radius in the
deformation process is not distorted.
The physical aspect. The relation between stresses and
deformations is described by Hooke’s law in shear
  G . (5.5)
 
Substituting the equation (5.4) in Hooke's law (5.5), we obtain
the stress distribution law in torsion
d
  G . (5.6)

dx
Study together with the law of stress distribution (5.6) the
equilibrium equation (5.3), we obtain

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