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P. 44

Figure 2.12



           is presented in the fig.2.12, b by shaded area. Then the total work
           is done by a force  P  equals to the area   OAB
                                         Р
                                   U      ,                       (2.33)
                                          2
           where  U –  the  potential  energy  of  deformation.  Substituting
           equation (2.11) into (2.33), we obtain:
                                        2
                                      Р l
                                  U     0  .                        (2.34)
                                      2ЕA
             To estimate the energy intensity of rod material define specific
           potential energy accumulated per unit volume.
                                     2
                               U    P l   1     2
                          u          0       x  ,                (2.35)
                           п
                               V    2EA Al     2E
                                            0
           or
                                      1
                                 u      ,                         (2.36)
                                  п      x  x
                                      2
             where V –  the rod volume.


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