Page 27 - 4560

qx 2
2a Px  2 qa 4
y   2 xdx  .
0 EJ z 3 EJ z
If you need to determine the deflection at the point where
the generalized force does not work, then at this point put a
fictitious force in the right direction. After differentiation
fictitious force is equated to zero and you perform the integration.

2.4 More’s integral

Let’s study the direct cross bending beam, loaded with an
arbitrary external load (fig. 2.4 a). This condition is called beam
freight.
Find the deflection at the point A . For this we should
unload beam and in the direction of the sought movement we
apply unit (non-dimensional) force P  . This condition of the
1
beam is called single.

27