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i  m
                                                              U   N  A kT                                  (2.2.4)
                                                           2  M





                       2.3 Work Done During Alteration of Gas Volume


                     When a gas expands, it pushes out on its boundary surfaces as they
                                                                 move       outward;         hence,       an
                                                                 expanding  gas  always  does  a

                                                                 positive  quantity  of  work.  To
                                                                 calculate  the  work  done  by  a
                                                                 thermodynamic  system  during  a
                                                                 volume  change,  let  us  consider  a

                                                                 solid  or  fluid  contained  in  a
                                                                 cylinder"-equipped            with        a
                                                                 movable piston, as shown in Fig.

                                                                 2.3.1  Suppose  that  the  cylinder
                                                                 has  a  cross-sectional  area  S  and
                       Figure  2.3.1
                                                                 that  the  pressure  exerted  by  the

                                                                 system at the piston face is p. The
            force exerted by the system is therefore  F               pS  If the piston moves out a

                                                  small distance  dx, the work  dA of this force
                                                  is
                                                                         dA   F  dx   pS  dx         (2.3.1)

                                                  But    Sdx     dV , i.e the change of volume of
                                                  system. Therefore,


                                                           dA   pdV                                     (2.3.2)
                                                  and in a finite change of volume from     V
                                                                                                        1
                 Figure  2.3.2                    to V we receive
                                                       2
                                                            V 2
                                                         A    pdV                                       (2.3.3)

                                                             V 1

                In  general,  the  pressure  of  the  system  may  vary  during  the  volume

            change, and the integral can be evaluated only when the pressure is known
            as  a  function  of  volume.  It  is  customary  to  represent  this  relationship
            graphically by plotting p as a function of V, as in Fig.2.3.2 Then Eq. (2.3.3)



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