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P. 128
Z x
d
f(ξ) dξ = f(x)
dx c
Z c
d
f(ξ) dξ = −f(x)
dx x
Z h Z h
d ∂f(ξ, x) 0 0
f(ξ, x) dξ = dξ + f(h, x)h − f(g, x)g
dx g g ∂x
121
