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The value of the required safety factor    1,4 3n     depends on
          several  factors  (appointment  details,  working  conditions,  the
          accuracy of existing loads, etc.) and selected in accordance with
          the accepted norms, standards, technical specifications or current
          experience in operating details.
          Safety factor  n  is the ratio of the boundary endurance defined for
          the details   , to the nominal value of the maximum stress that
                       rд
          occurs in the danger point details. Nominal voltage is the value
          that is determined by methods of strength of materials (without
          concentration, etc.).
          It is very easy to determine  n  in case of a symmetric cycle, as
          endurance border material at these cycles are known:
                                 
         – when bent  n    1д     1     ;                     (6.13)
                                 k 
                            a        a
                                   
         – when torsion  n    1д     1     .                  (6.14)
                                   k 
                              a        a
          In  the  asymmetric  cycle  situation  is  complicated  boundary
          condition  is  characterized  by  two  quantities:  the  average  stress
          and  the  corresponding  boundary  amplitude.  To  determine  the
          coefficients of safety we use limit stress diagram (diagram Hay).
          It is built in the coordinates    -   (fig. 6.5). Inside the region
                                        a    m
          bounded  by  the  coordinate  axes   ,     and  curves  of  stress,
                                             a    m
          there is no fracture in an infinite number of loading cycles.
          Usually  the  limit  stress  diagram  schematized.  Remove  an  area
          where  the  maximum  stress              exceeds  the  yield
                                         max    m    a
          stress  limit  of  the  material.  To  do  this,  through  the  point  D ,
                                                                    
          corresponding to the liquid limit, hold a straight angle  45  (fig.
          6.5), the equation which
                                       .                     (6.15)
                             max   m    a    т
          The initial section of the chart replacing line passing through the
          two  points  corresponding  to  the  symmetric  limit  cycle
           A     0;      1      and   limiting   the   pulsing   cycle
               m
                       a
           B         0   2 . The equation of this line is of the form
               m
                    a
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