Page 262 - 6193
P. 262
∆ ∆
∆ = 2 + ∙ ∙ ,
2 2
° ° ° °
∆ = 2 + ∙ 30° ∙ 60°=
=36.098°.
36.098°
180 tg 2
= = 1.035.
3.14 36.098°
2
400
∆ = 1.035 (cos 30° + cos 60°) = 282.8 м ≈ 283 м.
2
400
∆ = 1.035 (sin30° + sin 60°) = 282.8 м = 283 м.
2
∆ = 1.035 (sin30° ∙ cos 120° + sin60° ∙ cos150°) = −207 м.
∆ = 1.035 ∙ (sin30° ∙ sin120° + sin 60° ∙ sin 150°) =
= 179.3 м ≈179 м.
Координати кінцевої точки
= + ∆ , = 1760 + 179 = 1939 м,
= + ∆ , = −1650 − 207 = −1857 м,
= + ∆ , = 2000 + 283 = 2283 м,
= + ∆ , = 300 + 283 = 583 м.
263